proper maths questions

[mathsteacher]

sorry was celebrating with my leaving certs
pussy cat stick to want ur good at ...... brown nosing!

(a) using only the numbers 27, 40, 53, 72 and 91 and addition make the following numbers (each number can be used more then once)

____ + _____ + ______ = 190

____ + _____ + ______ = 146

____ + _____ + ______ = 158

____ + _____ + ______ = 145

____ + _____ + ______ = 178



(b) convert decimal number 258 to (i) binary (ii) octal (iii) hexadecimal

[benin]

sorry was celebrating with my leaving certs

jeysus thats sick...lol

[mathsteacher]

jeysus thats sick...lol

hows that sick lol, it was actually very nice

[sweet rebeka]

sorry was celebrating with my leaving certs
pussy cat stick to want ur good at ...... brown nosing!

(a) using only the numbers 27, 40, 53, 72 and 91 and addition make the following numbers (each number can be used more then once)

____ + _____ + ______ = 190

____ + _____ + ______ = 146

____ + _____ + ______ = 158

____ + _____ + ______ = 145

____ + _____ + ______ = 178



(b) convert decimal number 258 to (i) binary (ii) octal (iii) hexadecimal

91+72+27=190
40+53+53=146
27+40+91=158
27+27+91=145
53+53+72=178

[mathsteacher]

91+72+27=190
40+53+53=146
27+40+91=158
27+27+91=145
53+53+72=178

looks good the calculations
what about (b)

[sweet rebeka]

looks good the calculations
what about (b)

i let the (b) for others

[mathsteacher]

i let the (b) for others

ah right i knew there was a reason, we will wait for the IT experts lol

[susietranslut]

(b) convert decimal number 258 to (i) binary 100000010 ii) octal 402 (iii) hexadecimal 102

[mathsteacher]

(b) convert decimal number 258 to (i) binary 100000010 ii) octal 402 (iii) hexadecimal 102

excellent first post, well done

[mathsteacher]

Do i have to show my work

91+42+27=190
40+53+53=146
27+91+40=158
91+27+27=145
53+53+72=178

b) 100000010; 402;102


Convert 3133065982 dec to hex.

the more workings u show the better it looks for u!
do u want me to convert that great big dirty number?